2x^2+45X-275=0

Solution for 2x^2+45X-275=0 equation:

2x^2+45x-275=0

a = 2; b = 45; c = -275;
Δ = b2-4ac
Δ = 452-4·2·(-275)
Δ = 4225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4225}=65$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-65}{2*2}=\frac{-110}{4}
=-27+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+65}{2*2}=\frac{20}{4}
=5
$